The models of atom’s nucleus and table of elements.

Every subsequent element of the table of elements differs

The models of atom’s nucleus and table of elements.

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Model of atoms nucleus and table of elements.

 

Every subsequent element of the table of elements differs from the previous one in the amount of protons in its nucleus which is increased by one unit and the amount of neutrons is increased by several units in general. That means , that there are more neutrons in the nucleus than protons (without taking into consideration the lightest nucleuses). The scientific literature doesnt give any explanation of this strange correlation of neutrons number to the protons number.

It should be noted that for the construction of the model of atoms nucleus , He nucleuses have the same energies during the alpha-radioactivity. Thats why lets place all protons with the same number of neutrons on the nucleus external shell , that means , that on the same energy level only bosons can be found , and they are considered to be alpha-elements found on the nucleus external shell.

Lets place the rest of neutrons inside the nucleus , their task is to weaken the electrostatic field of protons repulsion. Supposing that the nucleus is spherical and protons and neutrons have the same radiuses , well get a model of nucleus for any element , which explains the number of neutrons ratio to the number of protons , which follows from the existence of nucleons in the atoms nucleus .

Radioactive decay is probably connected with the nucleus compression , because neutrons in the nucleus capacity weaken radial forces of protons repulsion with the growth of an elements ordinal number.

If nucleuses mass is primary and chemical qualities of an atom are secondary , than in the table of elements atomic weight must change continuously either down on across. Having constructed the table according to these features we have to leave four empty places after Lu and Lr in order to observe chemical qualities of elements . Determination of nucleus charge is probably necessity in discovering elements .

As a matter of fact elements are considered to be discovered based on their chemical qualities .

 

H

1He

2Li

3Be

4B

5C

6N

7O

8F

9Ne

10Na

11Mg12Al

13Si

14P1

5S

16Cl

17ArK

19Ca

20Sc

21Ti

22V

23Cr

24Mn

25Fe

26Co

27Ni 28Cu

29Zn

30Ga

31Ge

32As

33Se

34Br

35Kr

36Rb

37Sr

38Y

39Zr

40Nb

41Mo

42Tc

43Ru

44Rh

45Pd

46Ag

47Cd

48In

49Sn

50Sb

51Te

52I

53Xe

54Cs

55Ba

56La

57Ce

58Pr

59Nd

60Pm

61Sm

62Eu

63Gd

64Tb

65Dy

66Ho

67Er

68Tu

69Yb

70Lu

71?

72?

73?

74?

75Hf

76Ta

77W

78Re

79Os

80Ir

81Pt

82Au

83Hg

84Tl

85Pb

86Bi

87Po

88At

89Rn

90Fr

91Ra

92Ac

93Th

94Pa

95U

96Np

97Pu

98Am

99Cm

100Bk

101Cf

102Es

103Fm

104Md

105No

106Lr

107

In 1891 James Chardwik carried out researches and with the help of Rezerfords formula rated nucleuses charges for platinum-77,4 ; silver-46,3 ; copper-29,3 . These results almost coincided with ordinal numbers of these elements in the periodic table .

But the last lanthanide are radioactive ! According to our model of atoms nucleus radioactivity of the subsequent after lanthanide elements can be reduced , by bringing a shell inside the nucleus which consists of 4 protons or 4 alpha-elements.

But then defining the nucleuses charge of platinums atom on Chardwiks method , we would get again 77,4 ; because alpha-elements would disperse on the nucleuss external shell of an atom .

Thats why the question of more precise definition of nucleus charges of elements following the Hf , is raised .

This is probably the reason of the failure to get to the “ island of stability “ and seditious idea comes to the mine we build atomic electric power stations without knowing the definite amount of neutrons and protons in the nucleuses of uranium and plutonium .

 

http://www.amazon.com

 

Henadzi Filipenka , teacher of materials

 

HTTP:// HOME. URAL.RU/~FILIP

References:

Hehadzi Filipenka “Engineer” Moscow N4 1990 , N4 1991.

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